Congratulations to all problem solvers!

Problem 1 solutions

The correct solution is:

Julia had 39 beads, Kris had 21 and Anna had 12 beads.

Solutions by John O’Connor and Mrs. Knight’s class are presented below.

Their solutions differ in their approach to the problem solving.

Mrs. Knight’s students applied "hands-on" approach to problem solving, while John relied on analysis, pen and paper.

It is very instructive to read both solutions.

Name
John O'Connor
State/Country
NEW YORK
School
JFK middle school
age
11
Solution
I worked backwards. If they all had 24 at the end and A just gave J and K the same amount they each had then they had 12 each and A had 48.
K gave J and A the same amount that they each had therefore J had 6 K had 42 and A had 24.
J gave K and A the same amount that they had therefore J had 39 K had 21 and A had 12.
Other Interests
I like to play baseball & handball. I love school and my favorite subjects are science and math.
 

Name
Mrs. Knight's math class
State/Country
Georgia
School
Western Elementary School
age
11
Solution

There are 2 kids in my math class. To solve the problem we used beans instead of beads. We started at the end because it told us the number of beads that we should end up with. Each one of us (students and me) pretended to be one of the people in the problem. We worked backwards, and when the problem told us to lend we took. By working backwards we came up with a solution. Then we checked our answer 2 times to be certain. Julia had 39 beads, Anna had 12, and Kris had 21 to begin with.

The boys said, "We like doing this stuff. It is "more funner" than working out of the book!"

Other Interests
2 boys in class, like race cars and wrestling.