Tricky Sum
Problem #47
Deadline to submit the solution: September
30th , 2001
The sum of three whole numbers is 440.
The first number is twice smaller than the second number and seven
times larger than the third number. Find these numbers
Q1: The first number is ___.
Q2: The second number is ___.
Q3: The third number is ___.


Solutions:
Eddie from U.S.A
Grade: 3 Age: 8 School: Seawell School
Solution:
Q1: 280
Q2: 140
Q3: 20
If you start with the number 3 it is the easiest so you keep on it and
don"t give up you"ll find the answer so if you choose 20 as number 3 you
simply times 7 which equals 140 then you add another 140 then equals 280.
So now you add them{20,140,and 280} that then equals the answer.
About me: Last year I was active and also smart and now I am unactive
{ but still a little} and more smart I have many freinds { including girls
}.

Johnson from USA
Grade: 4 Age: 9 School: Upper School
Solution:
Q1: 140
Q2: 280
Q3: 20
X + 2X + 1/7X = 440
About me:

Tommy from USA
Grade: 4 Age: 9 School: Pond Hill
Solution:
Q1: 140
Q2: 280
Q3: 20
First number is 7 times larger than the third number. 7n + second # +
n = 440 The second number is twice as large as the first number 7n+14n+n=440
22n=440 n=20 First number = 7 times 20 = 140 Second number = 14 times
20 = 280 Third number = 20 140 + 280 + 20 = 440
About me: I love math and computers.
